Given a non-negative integer num
, return true
if num
can be expressed as the sum of any non-negative integer and its reverse, or false
otherwise.
Input: num = 443 Output: true Explanation: 172 + 271 = 443 so we return true.
Input: num = 63 Output: false Explanation: 63 cannot be expressed as the sum of a non-negative integer and its reverse so we return false.
Input: num = 181 Output: true Explanation: 140 + 041 = 181 so we return true. Note that when a number is reversed, there may be leading zeros.
0 <= num <= 105
class Solution:
def sumOfNumberAndReverse(self, num: int) -> bool:
return any(k + int(str(k)[::-1]) == num for k in range(num + 1))