You are given two strings current
and correct
representing two 24-hour times.
24-hour times are formatted as "HH:MM"
, where HH
is between 00
and 23
, and MM
is between 00
and 59
. The earliest 24-hour time is 00:00
, and the latest is 23:59
.
In one operation you can increase the time current
by 1
, 5
, 15
, or 60
minutes. You can perform this operation any number of times.
Return the minimum number of operations needed to convert current
to correct
.
Input: current = "02:30", correct = "04:35" Output: 3 Explanation: We can convert current to correct in 3 operations as follows: - Add 60 minutes to current. current becomes "03:30". - Add 60 minutes to current. current becomes "04:30". - Add 5 minutes to current. current becomes "04:35". It can be proven that it is not possible to convert current to correct in fewer than 3 operations.
Input: current = "11:00", correct = "11:01" Output: 1 Explanation: We only have to add one minute to current, so the minimum number of operations needed is 1.
current
andcorrect
are in the format"HH:MM"
current <= correct
class Solution:
def convertTime(self, current: str, correct: str) -> int:
current = int(current[:2]) * 60 + int(current[3:])
correct = int(correct[:2]) * 60 + int(correct[3:])
diff = correct - current + (1440 if correct < current else 0)
ret = 0
ret, diff = ret + diff // 60, diff % 60
ret, diff = ret + diff // 15, diff % 15
ret, diff = ret + diff // 5, diff % 5
ret += diff
return ret