You are given an array of strings nums
and an integer k
. Each string in nums
represents an integer without leading zeros.
Return the string that represents the kth
largest integer in nums
.
Note: Duplicate numbers should be counted distinctly. For example, if nums
is ["1","2","2"]
, "2"
is the first largest integer, "2"
is the second-largest integer, and "1"
is the third-largest integer.
Input: nums = ["3","6","7","10"], k = 4 Output: "3" Explanation: The numbers in nums sorted in non-decreasing order are ["3","6","7","10"]. The 4th largest integer in nums is "3".
Input: nums = ["2","21","12","1"], k = 3 Output: "2" Explanation: The numbers in nums sorted in non-decreasing order are ["1","2","12","21"]. The 3rd largest integer in nums is "2".
Input: nums = ["0","0"], k = 2 Output: "0" Explanation: The numbers in nums sorted in non-decreasing order are ["0","0"]. The 2nd largest integer in nums is "0".
1 <= k <= nums.length <= 104
1 <= nums[i].length <= 100
nums[i]
consists of only digits.nums[i]
will not have any leading zeros.
class Solution:
def kthLargestNumber(self, nums: List[str], k: int) -> str:
return sorted(nums, key=lambda num: (len(num), num))[-k]