You are given an integer array nums
and an integer k
.
In one operation, you can pick two numbers from the array whose sum equals k
and remove them from the array.
Return the maximum number of operations you can perform on the array.
Input: nums = [1,2,3,4], k = 5 Output: 2 Explanation: Starting with nums = [1,2,3,4]: - Remove numbers 1 and 4, then nums = [2,3] - Remove numbers 2 and 3, then nums = [] There are no more pairs that sum up to 5, hence a total of 2 operations.
Input: nums = [3,1,3,4,3], k = 6 Output: 1 Explanation: Starting with nums = [3,1,3,4,3]: - Remove the first two 3's, then nums = [1,4,3] There are no more pairs that sum up to 6, hence a total of 1 operation.
1 <= nums.length <= 105
1 <= nums[i] <= 109
1 <= k <= 109
use std::collections::HashMap;
impl Solution {
pub fn max_operations(nums: Vec<i32>, k: i32) -> i32 {
let mut count = HashMap::new();
let mut ret = 0;
for num in nums {
if *count.get(&(k - num)).unwrap_or(&0) > 0 {
*count.get_mut(&(k - num)).unwrap() -= 1;
ret += 1;
} else {
*count.entry(num).or_insert(0) += 1;
}
}
ret
}
}