Given an integer array arr
, return true
if there are three consecutive odd numbers in the array. Otherwise, return false
.
Input: arr = [2,6,4,1] Output: false Explanation: There are no three consecutive odds.
Input: arr = [1,2,34,3,4,5,7,23,12] Output: true Explanation: [5,7,23] are three consecutive odds.
1 <= arr.length <= 1000
1 <= arr[i] <= 1000
class Solution:
def threeConsecutiveOdds(self, arr: List[int]) -> bool:
for i in range(len(arr) - 2):
if arr[i] % 2 == arr[i + 1] % 2 == arr[i + 2] % 2 == 1:
return True
return False