Given a list of folders, remove all sub-folders in those folders and return in any order the folders after removing.
If a folder[i]
is located within another folder[j]
, it is called a sub-folder of it.
The format of a path is one or more concatenated strings of the form: /
followed by one or more lowercase English letters. For example, /leetcode
and /leetcode/problems
are valid paths while an empty string and /
are not.
Input: folder = ["/a","/a/b","/c/d","/c/d/e","/c/f"] Output: ["/a","/c/d","/c/f"] Explanation: Folders "/a/b/" is a subfolder of "/a" and "/c/d/e" is inside of folder "/c/d" in our filesystem.
Input: folder = ["/a","/a/b/c","/a/b/d"] Output: ["/a"] Explanation: Folders "/a/b/c" and "/a/b/d/" will be removed because they are subfolders of "/a".
Input: folder = ["/a/b/c","/a/b/ca","/a/b/d"] Output: ["/a/b/c","/a/b/ca","/a/b/d"]
1 <= folder.length <= 4 * 10^4
2 <= folder[i].length <= 100
folder[i]
contains only lowercase letters and '/'folder[i]
always starts with character '/'- Each folder name is unique.
impl Solution {
pub fn remove_subfolders(folder: Vec<String>) -> Vec<String> {
let mut folder = folder.into_iter().map(|s| s + "/").collect::<Vec<_>>();
folder.sort_unstable();
let mut ret = Vec::new();
for f in folder {
if ret.is_empty() || !f.starts_with(ret.last().unwrap()) {
ret.push(f);
}
}
ret.iter_mut().for_each(|s| {
s.pop();
});
ret
}
}