There is a room with n
bulbs labeled from 1
to n
that all are turned on initially, and four buttons on the wall. Each of the four buttons has a different functionality where:
- Button 1: Flips the status of all the bulbs.
- Button 2: Flips the status of all the bulbs with even labels (i.e.,
2, 4, ...
). - Button 3: Flips the status of all the bulbs with odd labels (i.e.,
1, 3, ...
). - Button 4: Flips the status of all the bulbs with a label
j = 3k + 1
wherek = 0, 1, 2, ...
(i.e.,1, 4, 7, 10, ...
).
You must make exactly presses
button presses in total. For each press, you may pick any of the four buttons to press.
Given the two integers n
and presses
, return the number of different possible statuses after performing all presses
button presses.
Input: n = 1, presses = 1 Output: 2 Explanation: Status can be: - [off] by pressing button 1 - [on] by pressing button 2
Input: n = 2, presses = 1 Output: 3 Explanation: Status can be: - [off, off] by pressing button 1 - [on, off] by pressing button 2 - [off, on] by pressing button 3
Input: n = 3, presses = 1 Output: 4 Explanation: Status can be: - [off, off, off] by pressing button 1 - [off, on, off] by pressing button 2 - [on, off, on] by pressing button 3 - [off, on, on] by pressing button 4
1 <= n <= 1000
0 <= presses <= 1000
impl Solution {
pub fn flip_lights(n: i32, presses: i32) -> i32 {
match (n, presses) {
(_, 0) => 1,
(1, _) => 2,
(2, 1) => 3,
(2, _) => 4,
(_, 1) => 4,
(_, 2) => 7,
_ => 8,
}
}
}