Given an array consisting of n
integers, find the contiguous subarray of given length k
that has the maximum average value. And you need to output the maximum average value.
Input: [1,12,-5,-6,50,3], k = 4 Output: 12.75 Explanation: Maximum average is (12-5-6+50)/4 = 51/4 = 12.75
- 1 <=
k
<=n
<= 30,000. - Elements of the given array will be in the range [-10,000, 10,000].
impl Solution {
pub fn find_max_average(nums: Vec<i32>, k: i32) -> f64 {
let k = k as usize;
let mut sum: i32 = nums.iter().take(k).sum();
let mut max_sum = sum;
for i in k..nums.len() {
sum += nums[i] - nums[i - k];
max_sum = max_sum.max(sum);
}
max_sum as f64 / k as f64
}
}