Given a binary tree, you need to compute the length of the diameter of the tree. The diameter of a binary tree is the length of the longest path between any two nodes in a tree. This path may or may not pass through the root.
Given a binary tree
1
/ \
2 3
/ \
4 5
Return 3, which is the length of the path [4,2,1,3] or [5,2,1,3].
Note: The length of path between two nodes is represented by the number of edges between them.
# Definition for a binary tree node.
# class TreeNode:
# def __init__(self, x):
# self.val = x
# self.left = None
# self.right = None
class Solution:
def diameterOfBinaryTree(self, root: TreeNode) -> int:
def helper(root: TreeNode) -> (int, int):
if not root:
return (-1, 0)
l_longer, l_diameter = helper(root.left)
r_longer, r_diameter = helper(root.right)
l_longer += 1
r_longer += 1
return (max(l_longer, r_longer), max(l_diameter, r_diameter, l_longer + r_longer))
return helper(root)[1]