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fixes join.py and split.py action and requirements error #12438

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Dec 29, 2024
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4 changes: 2 additions & 2 deletions requirements.txt
Original file line number Diff line number Diff line change
@@ -1,5 +1,5 @@
beautifulsoup4
fake_useragent
fake-useragent
imageio
keras
lxml
Expand All @@ -11,7 +11,7 @@ pillow
requests
rich
scikit-learn
sphinx_pyproject
sphinx-pyproject
statsmodels
sympy
tweepy
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58 changes: 17 additions & 41 deletions strings/join.py
Original file line number Diff line number Diff line change
@@ -1,51 +1,27 @@
"""
Program to join a list of strings with a separator
"""


def join(separator: str, separated: list[str]) -> str:
"""
Joins a list of strings using a separator
and returns the result.

:param separator: Separator to be used
for joining the strings.
:param separated: List of strings to be joined.

:return: Joined string with the specified separator.

Examples:

>>> join("", ["a", "b", "c", "d"])
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@Kaaserne Kaaserne Dec 18, 2024

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What's the reason these got removed? I've never used doctest before but I think this has something to do with testing. Maybe you can also add:

"""
>>> join(',', ['', '', ''])
',,'
"""

'abcd'
>>> join("#", ["a", "b", "c", "d"])
'a#b#c#d'
>>> join("#", "a")
'a'
>>> join(" ", ["You", "are", "amazing!"])
'You are amazing!'
Custom implementation of the join() function.
This function manually concatenates the strings in the list,
using the provided separator, without relying on str.join().

This example should raise an
exception for non-string elements:
>>> join("#", ["a", "b", "c", 1])
Traceback (most recent call last):
...
Exception: join() accepts only strings
:param separator: The separator to place between strings.
:param separated: A list of strings to join.

Additional test case with a different separator:
>>> join("-", ["apple", "banana", "cherry"])
'apple-banana-cherry'
:return: A single string with elements joined by the separator.

Check failure on line 11 in strings/join.py

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Ruff (W293)

strings/join.py:11:1: W293 Blank line contains whitespace
:raises Exception: If any element in the list is not a string.
"""
if not all(isinstance(word_or_phrase, str) for word_or_phrase in separated):
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@Kaaserne Kaaserne Dec 18, 2024

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I think this if statement, with the removal of all, can be placed inside the for-loop. That way we only iterate over the sequence once, instead of twice.

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Thank you for your advice. sure lemme check

raise Exception("join() accepts only strings")

joined = ""
for word_or_phrase in separated:
if not isinstance(word_or_phrase, str):
raise Exception("join() accepts only strings")
joined += word_or_phrase + separator
# Manually handle concatenation
result = ""
for i, element in enumerate(separated):
result += element
if i < len(separated) - 1: # Add separator only between elements
result += separator

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@Kaaserne can you please review it?

# Remove the trailing separator
# by stripping it from the result
return joined.strip(separator)
return result


if __name__ == "__main__":
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17 changes: 13 additions & 4 deletions strings/split.py
Original file line number Diff line number Diff line change
Expand Up @@ -17,14 +17,23 @@ def split(string: str, separator: str = " ") -> list:
"""

split_words = []

last_index = 0

for index, char in enumerate(string):
if char == separator:
split_words.append(string[last_index:index])
split_words.append(
string[last_index:index]
) # Add substring between separators
last_index = index + 1
elif index + 1 == len(string):
split_words.append(string[last_index : index + 1])
elif index + 1 == len(
string
): # If at the last character, handle trailing separator
split_words.append(string[last_index:]) # Add the last part of the string

# If the string ends with a separator, ensure an empty string is added
if string and string[-1] == separator:
split_words.append("")

return split_words


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