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Why is UPDI pin having Vcc as output? #1188
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You need to first set the UPDI pin as GPIO pin to be able to use it as GPIO pin. |
Thanks for your answer. |
Because the UPDI is HIGH in it's idle state and it has a internal pullup resistor. That's what you are measuring. If you connect a led to it, you will see it lights up a little (current flowing through the pullup resistor). If you want to read more about the half-duplex protocol over one wire, this Microchip application note may be of interest to you. |
Thanks, that explains it very well! |
"Unless not connected" means it is connected. If not connected it cannot draw current. |
Hi there,
simple circuit: LED at PA1 :-)
Trying some blinky-stuff, and I wonder why the UPDI pin is showing +Vcc
To save some energy, I took this function and I thought that PIN0 was the UPDI pin:
What am I missing? Do I need to connect UPDI pin if not needed?
Thanks a lot!
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