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Q:如何实现在父亲本体上定义一个rule(可能是关系计算规则或者属性计算规则),其所有层子类应该都继承这个规则,而无须在子类重复定义该规则。
假设有结构 先申明不按建模最佳实践来设计一个分类解决,我想用继承方式; 我弄个schema文件如下:
FilmStat(电影明星):ConceptType hypernymPredicate: isA Person(人):ConceptType hypernymPredicate: isA ArtificialObject(作品): ConceptType hypernymPredicate: isA FilmDirector(导演):EntityType properties: IND#belongTo(属于):Person age(年龄):Integer gender(性别):Text PopularFilmStat(流行电影明星):EntityType properties: IND#belongTo(属于):FilmStat age(年龄):Integer gender(性别):Text Film(电影):EntityType properties: filmBudget(投入):Integer filmGross(票房):Integer IND#belongTo(属于):ArtificialObject relations: starOfFilm(主演):FilmStat directOfFilm(被导演):FilmDirector oldestOfStat(xx明星):FilmStat rule:[[ STRUCTURE { (o) } CONSTRAINT { R2("xx"): o.name in ["张三"] } ]]
生成的图如下:
这种多层级继承的结构,spg如何定义继承schema
如果用belongTo来定义,不符合继承逻辑,并且它要求 a concept type to conform to the definition必须是概念类型,但是概念类型没办法继承且不能定义属性和规则。
如果用isA,则没办法多次继承,形如图上应该”电影明星“isA”人“;
后面在查找白皮书,看到4.3.1.1原文内容如下:
subClassOf 谓词通过定义节点类型之间的层级关系来补充类型继承的语义,在定义节点类型 Class 时,在后面跟上 SUBCLASSOF 关键字引导的类型名称即可实现继承。 // 定义 User 类的两个子类 CREATE ENTITY TYPE (Person {age INT, OPTIONAL father Person}) SUBCLASSOF (User); CREATE ENTITY TYPE (LegalPerson {amount INT, legalId STRING}) SUBCLASSOF (User);
在v0.5的schema上如何定义subClassOf,或者怎么实现继承关系;
The text was updated successfully, but these errors were encountered:
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Q:如何实现在父亲本体上定义一个rule(可能是关系计算规则或者属性计算规则),其所有层子类应该都继承这个规则,而无须在子类重复定义该规则。
假设有结构
先申明不按建模最佳实践来设计一个分类解决,我想用继承方式;
我弄个schema文件如下:
生成的图如下:
这种多层级继承的结构,spg如何定义继承schema
如果用belongTo来定义,不符合继承逻辑,并且它要求 a concept type to conform to the definition必须是概念类型,但是概念类型没办法继承且不能定义属性和规则。
如果用isA,则没办法多次继承,形如图上应该”电影明星“isA”人“;
后面在查找白皮书,看到4.3.1.1原文内容如下:
在v0.5的schema上如何定义subClassOf,或者怎么实现继承关系;
The text was updated successfully, but these errors were encountered: